2.65+3(1+d)+(2+d)+(3+d)=2.65

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Solution for 2.65+3(1+d)+(2+d)+(3+d)=2.65 equation: 



2.65+3(1+d)+(2+d)+(3+d)=2.65

We move all terms to the left:

2.65+3(1+d)+(2+d)+(3+d)-(2.65)=0

We add all the numbers together, and all the variables

3(d+1)+(d+2)+(d+3)+2.65-(2.65)=0

We add all the numbers together, and all the variables

3(d+1)+(d+2)+(d+3)=0

We multiply parentheses

3d+(d+2)+(d+3)+3=0

We get rid of parentheses

3d+d+d+2+3+3=0

We add all the numbers together, and all the variables

5d+8=0

We move all terms containing d to the left, all other terms to the right

5d=-8

d=-8/5

d=-1+3/5

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