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2.65x^2=4.11
We move all terms to the left:
2.65x^2-(4.11)=0
We add all the numbers together, and all the variables
2.65x^2-4.11=0
a = 2.65; b = 0; c = -4.11;
Δ = b2-4ac
Δ = 02-4·2.65·(-4.11)
Δ = 43.566
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{43.566}}{2*2.65}=\frac{0-\sqrt{43.566}}{5.3} =-\frac{\sqrt{}}{5.3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{43.566}}{2*2.65}=\frac{0+\sqrt{43.566}}{5.3} =\frac{\sqrt{}}{5.3} $
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