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2.75x^2-0.3x-0.0225=0
a = 2.75; b = -0.3; c = -0.0225;
Δ = b2-4ac
Δ = -0.32-4·2.75·(-0.0225)
Δ = 0.3375
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{0.3375}}{2*2.75}=\frac{0.3-\sqrt{0.3375}}{5.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{0.3375}}{2*2.75}=\frac{0.3+\sqrt{0.3375}}{5.5} $
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