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2.8=y2
We move all terms to the left:
2.8-(y2)=0
We add all the numbers together, and all the variables
-1y^2+2.8=0
a = -1; b = 0; c = +2.8;
Δ = b2-4ac
Δ = 02-4·(-1)·2.8
Δ = 11.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{11.2}}{2*-1}=\frac{0-\sqrt{11.2}}{-2} =-\frac{\sqrt{}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{11.2}}{2*-1}=\frac{0+\sqrt{11.2}}{-2} =\frac{\sqrt{}}{-2} $
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