2/((2/x)+1)

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Solution for 2/((2/x)+1) equation: 


D( x )

x = 0

2/x+1 = 0

x = 0

x = 0

2/x+1 = 0

2/x+1 = 0

2*x^-1 = -1 // : 2

x^-1 = -1/2

-1 < 0

1/(x^1) = -1/2 // * x^1

1 = -1/2*x^1 // : -1/2

-2 = x^1

x = -2

x in (-oo:-2) U (-2:0) U (0:+oo)

2/(2/x+1) = 0

2/(2*x^-1+1) = 0

x belongs to the empty set

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