2/(1+n)=-1/2n

Solution for 2/(1+n)=-1/2n equation:

2/(1+n)=-1/2n

We move all terms to the left:

2/(1+n)-(-1/2n)=0


Domain of the equation: (1+n)!=0

We move all terms containing n to the left, all other terms to the right

n!=-1

n∈R



Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

2/(n+1)-(-1/2n)=0

We get rid of parentheses

2/(n+1)+1/2n=0

We calculate fractions


4n/(2n^2+2n)+(1*(n+1))/(2n^2+2n)=0


We calculate terms in parentheses: +(1*(n+1))/(2n^2+2n), so:

1*(n+1))/(2n^2+2n

We add all the numbers together, and all the variables

2n+1*(n+1))/(2n^2

We multiply all the terms by the denominator


2n*(2n^2+1*(n+1))

Back to the equation:

+(2n*(2n^2+1*(n+1)))


We multiply all the terms by the denominator


4n+((2n*(2n^2+1*(n+1))))*(2n^2+2n)=0


We calculate terms in parentheses: +((2n*(2n^2+1*(n+1))))*(2n^2+2n), so:

(2n*(2n^2+1*(n+1))))*(2n^2+2n

We add all the numbers together, and all the variables

2n+(2n*(2n^2+1*(n+1))))*(2n^2

Back to the equation:

+(2n+(2n*(2n^2+1*(n+1))))*(2n^2)