2/(1-x)=(3x+4)

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Solution for 2/(1-x)=(3x+4) equation: 



2/(1-x)=(3x+4)

We move all terms to the left:

2/(1-x)-((3x+4))=0



Domain of the equation: (1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-1

x!=-1/-1

x!=1

x∈R



We add all the numbers together, and all the variables

2/(-1x+1)-((3x+4))=0

We multiply all the terms by the denominator


-(((3x+4)))*(-1x+1)+2=0



We calculate terms in parentheses: -(((3x+4)))*(-1x+1), so:

((3x+4)))*(-1x+1

We add all the numbers together, and all the variables

-1x+((3x+4)))*(+1

Back to the equation:

-(-1x+((3x+4)))*(+1)



We add all the numbers together, and all the variables

-(-1x+((3x+4)))*1+2=0

We move all terms containing x to the left, all other terms to the right

-(-1x+((3x+4)))*1=-2

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