2/(15d)-3/(5d)=35

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Solution for 2/(15d)-3/(5d)=35 equation: 


D( d )

15*d = 0

5*d = 0

15*d = 0

15*d = 0

15*d = 0 // : 15

d = 0

5*d = 0

5*d = 0

5*d = 0 // : 5

d = 0

d in (-oo:0) U (0:+oo)

2/(15*d)-(3/(5*d)) = 35 // - 35

2/(15*d)-(3/(5*d))-35 = 0

2/(15*d)+(-3/5)*d^-1-35 = 0

-7/15*d^-1 = 35 // : -7/15

d^-1 = -75

-1 < 0

1/(d^1) = -75 // * d^1

1 = -75*d^1 // : -75

-1/75 = d^1

d = -1/75

d = -1/75

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