2/(3x)+4/x=7/(x+1)

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Solution for 2/(3x)+4/x=7/(x+1) equation:


D( x )

3*x = 0

x = 0

x+1 = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x = 0

x = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

2/(3*x)+4/x = 7/(x+1) // - 7/(x+1)

2/(3*x)-(7/(x+1))+4/x = 0

2/(3*x)-7*(x+1)^-1+4/x = 0

2/(3*x)-7/(x+1)+4/x = 0

(-7*3*x*x)/(3*x*x*(x+1))+(2*x*(x+1))/(3*x*x*(x+1))+(3*4*x*(x+1))/(3*x*x*(x+1)) = 0

2*x*(x+1)+3*4*x*(x+1)-7*3*x*x = 0

12*x^2-19*x^2+2*x+12*x = 0

14*x-7*x^2 = 0

14*x-7*x^2 = 0

7*x*(2-x) = 0

2-x = 0 // - 2

-x = -2 // * -1

x = 2

7*x*(x-2) = 0

(7*x*(x-2))/(3*x*x*(x+1)) = 0

(7*x*(x-2))/(3*x*x*(x+1)) = 0 // * 3*x*x*(x+1)

7*x*(x-2) = 0

( 7*x )

7*x = 0 // : 7

x = 0

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 0}

x = 2

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