2/(3x-1)+(3/3x+1)=5/3x

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Solution for 2/(3x-1)+(3/3x+1)=5/3x equation: 



2/(3x-1)+(3/3x+1)=5/3x

We move all terms to the left:

2/(3x-1)+(3/3x+1)-(5/3x)=0



Domain of the equation: (3x-1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=1

x!=1/3

x!=1/3

x∈R





Domain of the equation: 3x+1)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2/(3x-1)+(3/3x+1)-(+5/3x)=0

We get rid of parentheses

2/(3x-1)+3/3x-5/3x+1=0

We calculate fractions


6x/(9x^2-3x)+(-15x+8)/(9x^2-3x)+1=0

We multiply all the terms by the denominator


6x+(-15x+8)+1*(9x^2-3x)=0

We get rid of parentheses

6x-15x+1*(9x^2-3x)+8=0

We add all the numbers together, and all the variables

-9x+1*(9x^2-3x)+8=0

We move all terms containing x to the left, all other terms to the right

-9x+1*(9x^2-3x)=-8

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