2/(4x+x)=96

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Solution for 2/(4x+x)=96 equation: 



2/(4x+x)=96

We move all terms to the left:

2/(4x+x)-(96)=0



Domain of the equation: (4x+x)!=0

x∈R



We add all the numbers together, and all the variables

2/(+5x)-96=0

We multiply all the terms by the denominator


-96*(+5x)+2=0

We multiply parentheses

-480x+2=0

We move all terms containing x to the left, all other terms to the right

-480x=-2

x=-2/-480

x=1/240

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