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2/(4x-1)=1/3x
We move all terms to the left:
2/(4x-1)-(1/3x)=0
Domain of the equation: (4x-1)!=0
We move all terms containing x to the left, all other terms to the right
4x!=1
x!=1/4
x!=1/4
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/(4x-1)-(+1/3x)=0
We get rid of parentheses
2/(4x-1)-1/3x=0
We calculate fractions
6x/(12x^2-3x)+(-1*(4x-1))/(12x^2-3x)=0
We calculate terms in parentheses: +(-1*(4x-1))/(12x^2-3x), so:We multiply all the terms by the denominator
-1*(4x-1))/(12x^2-3x
We add all the numbers together, and all the variables
-3x-1*(4x-1))/(12x^2
We multiply all the terms by the denominator
-3x*(12x^2-1*(4x-1))
Back to the equation:
+(-3x*(12x^2-1*(4x-1)))
6x+((-3x*(12x^2-1*(4x-1))))*(12x^2-3x)=0
We calculate terms in parentheses: +((-3x*(12x^2-1*(4x-1))))*(12x^2-3x), so:
(-3x*(12x^2-1*(4x-1))))*(12x^2-3x
We add all the numbers together, and all the variables
-3x+(-3x*(12x^2-1*(4x-1))))*(12x^2
Back to the equation:
+(-3x+(-3x*(12x^2-1*(4x-1))))*(12x^2)
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