2/(5q-5)=-5/(3q+1)

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Solution for 2/(5q-5)=-5/(3q+1) equation:



2/(5q-5)=-5/(3q+1)
We move all terms to the left:
2/(5q-5)-(-5/(3q+1))=0
Domain of the equation: (5q-5)!=0
We move all terms containing q to the left, all other terms to the right
5q!=5
q!=5/5
q!=1
q∈R
Domain of the equation: (3q+1))!=0
q∈R
We calculate fractions
6q/((5q-5)*(3q+1)))+(-(-5*(5q-5))/((5q-5)*(3q+1)))=0
We calculate terms in parentheses: -(-5*(5q-5))/((5q-5)*(3q+1))), so:
-5*(5q-5))/((5q-5)*(3q+1))
We multiply all the terms by the denominator
-5*(5q-5))
We multiply parentheses
-25q-
We add all the numbers together, and all the variables
-25q
Back to the equation:
-(-25q)
We get rid of parentheses
6q/((5q-5)*(3q+1)))+(+25q=0
We multiply all the terms by the denominator
6q+25q*((5q-5)*(3q+1)))+(=0

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