2/(7(3x-2))=56

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Solution for 2/(7(3x-2))=56 equation: 


D( x )

7*(3*x-2) = 0

7*(3*x-2) = 0

7*(3*x-2) = 0

( 3*x-2 )

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

( 7 )

7 = 0

x belongs to the empty set

x in (-oo:2/3) U (2/3:+oo)

2/(7*(3*x-2)) = 56 // - 56

2/(7*(3*x-2))-56 = 0

2/(7*(3*x-2))+(-56*7*(3*x-2))/(7*(3*x-2)) = 0

2-56*7*(3*x-2) = 0

786-1176*x = 0

(786-1176*x)/(7*(3*x-2)) = 0

(786-1176*x)/(7*(3*x-2)) = 0 // * 7*(3*x-2)

786-1176*x = 0

786-1176*x = 0 // - 786

-1176*x = -786 // : -1176

x = -786/(-1176)

x = 131/196

x = 131/196

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