2/(g+3)+1/(g+1)=0

Simple and best practice solution for 2/(g+3)+1/(g+1)=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 2/(g+3)+1/(g+1)=0 equation: 



2/(g+3)+1/(g+1)=0



Domain of the equation: (g+3)!=0

We move all terms containing g to the left, all other terms to the right

g!=-3

g∈R





Domain of the equation: (g+1)!=0

We move all terms containing g to the left, all other terms to the right

g!=-1

g∈R



We calculate fractions


(2g+2)/((g+3)*(g+1))+(1*(g+3))/((g+3)*(g+1))=0



We calculate terms in parentheses: +(2g+2)/((g+3)*(g+1)), so:

2g+2)/((g+3)*(g+1)

We multiply all the terms by the denominator


2g*((g+3)*(g+1)+2)

Back to the equation:

+(2g*((g+3)*(g+1)+2))





We calculate terms in parentheses: +(1*(g+3))/((g+3)*(g+1)), so:

1*(g+3))/((g+3)*(g+1)

We multiply all the terms by the denominator


1*(g+3))

Back to the equation:

+(1*(g+3)))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





We calculate terms in parentheses: +(2g*((g+3)*(g+1)+2)), so:

2g*((g+3)*(g+1)+2)





We calculate terms in parentheses: +(1*(g+3))), so:

1*(g+3))





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
See similar equations:

			

				| 1/5+d=4/5 |
| 1=9-8y |
| ∣2x-3∣=-1 |
| 8x+35=11x23 |
| 10x=3+7x |
| 15+10=-5(9x-5) |
| -9t+16=-8t |
| 2x=x-45 |
| -12+33=-3(x+1) |
| |2p-1|=|1-2p| |
| 5x+6-x=20 |
| 60-40/4=50+n |
| 7(x+14)-5=12x+53 |
| 28-6x=2 |
| u–11=–15 |
| 84-u=169 |
| |x-11|=12 |
| -3(m-3)=-4m+5 |
| 24+7t=8t+24 |
| 9+11=-5(2x-4) |
| -10x-50+66=-34 |
| 16=4-6w |
| 7x+3-4x=-3(x+4) |
| 5(4x+9)=-29+54 |
| 0.75x+1=0.50x-4.5 |
| z/3–10=–13 |
| z3–10=–13 |
| -14w+10=-16w |
| 3(4x+6)=-20+2 |
| m+(m+10)+3m=180 |
| 6x+5-x=20 |
| x/2+x-2/4=x+4/2 |
			
			

			
			
		

	
            

		
				
Equations solver categories