2/(t+2)=3/(t-5)

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Solution for 2/(t+2)=3/(t-5) equation: 


D( t )

t-5 = 0

t+2 = 0

t-5 = 0

t-5 = 0

t-5 = 0 // + 5

t = 5

t+2 = 0

t+2 = 0

t+2 = 0 // - 2

t = -2

t in (-oo:-2) U (-2:5) U (5:+oo)

2/(t+2) = 3/(t-5) // - 3/(t-5)

2/(t+2)-(3/(t-5)) = 0

2/(t+2)-3*(t-5)^-1 = 0

2/(t+2)-3/(t-5) = 0

(2*(t-5))/((t+2)*(t-5))+(-3*(t+2))/((t+2)*(t-5)) = 0

2*(t-5)-3*(t+2) = 0

-t-16 = 0

(-t-16)/((t+2)*(t-5)) = 0

(-t-16)/((t+2)*(t-5)) = 0 // * (t+2)*(t-5)

-t-16 = 0

-t-16 = 0 // + 16

-t = 16 // * -1

t = -16

t = -16

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