2/(w+1)=-6+(1/(w+2))

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Solution for 2/(w+1)=-6+(1/(w+2)) equation: 


D( w )

w+1 = 0

w+2 = 0

w+1 = 0

w+1 = 0

w+1 = 0 // - 1

w = -1

w+2 = 0

w+2 = 0

w+2 = 0 // - 2

w = -2

w in (-oo:-2) U (-2:-1) U (-1:+oo)

2/(w+1) = 1/(w+2)-6 // - 1/(w+2)-6

2/(w+1)-(1/(w+2))+6 = 0

2/(w+1)-(w+2)^-1+6 = 0

2/(w+1)-1/(w+2)+6 = 0

(2*(w+2))/((w+1)*(w+2))+(-1*(w+1))/((w+1)*(w+2))+(6*(w+1)*(w+2))/((w+1)*(w+2)) = 0

2*(w+2)-1*(w+1)+6*(w+1)*(w+2) = 0

6*w^2+w+18*w+3+12 = 0

6*w^2+19*w+15 = 0

6*w^2+19*w+15 = 0

6*w^2+19*w+15 = 0

DELTA = 19^2-(4*6*15)

DELTA = 1

DELTA > 0

w = (1^(1/2)-19)/(2*6) or w = (-1^(1/2)-19)/(2*6)

w = -3/2 or w = -5/3

(w+5/3)*(w+3/2) = 0

((w+5/3)*(w+3/2))/((w+1)*(w+2)) = 0

((w+5/3)*(w+3/2))/((w+1)*(w+2)) = 0 // * (w+1)*(w+2)

(w+5/3)*(w+3/2) = 0

( w+3/2 )

w+3/2 = 0 // - 3/2

w = -3/2

( w+5/3 )

w+5/3 = 0 // - 5/3

w = -5/3

w in { -3/2, -5/3 }

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