2/(x+1)=5/(3x-2)

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Solution for 2/(x+1)=5/(3x-2) equation: 



2/(x+1)=5/(3x-2)

We move all terms to the left:

2/(x+1)-(5/(3x-2))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (3x-2))!=0

x∈R



We calculate fractions


6x/((x+1)*(3x-2)))+(-(5*(x+1))/((x+1)*(3x-2)))=0



We calculate terms in parentheses: -(5*(x+1))/((x+1)*(3x-2))), so:

5*(x+1))/((x+1)*(3x-2))

We multiply all the terms by the denominator


5*(x+1))

We multiply parentheses

5x+

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We add all the numbers together, and all the variables

-5x+6x/((x+1)*(3x-2)))+(=0

We multiply all the terms by the denominator


-5x*((x+1)*(3x-2)))+(+6x=0

We add all the numbers together, and all the variables

6x-5x*((x+1)*(3x-2)))+(=0

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