2/(x+1)=5/(3x-2)

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Solution for 2/(x+1)=5/(3x-2) equation:



2/(x+1)=5/(3x-2)
We move all terms to the left:
2/(x+1)-(5/(3x-2))=0
Domain of the equation: (x+1)!=0
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
Domain of the equation: (3x-2))!=0
x∈R
We calculate fractions
6x/((x+1)*(3x-2)))+(-(5*(x+1))/((x+1)*(3x-2)))=0
We calculate terms in parentheses: -(5*(x+1))/((x+1)*(3x-2))), so:
5*(x+1))/((x+1)*(3x-2))
We multiply all the terms by the denominator
5*(x+1))
We multiply parentheses
5x+
We add all the numbers together, and all the variables
5x
Back to the equation:
-(5x)
We add all the numbers together, and all the variables
-5x+6x/((x+1)*(3x-2)))+(=0
We multiply all the terms by the denominator
-5x*((x+1)*(3x-2)))+(+6x=0
We add all the numbers together, and all the variables
6x-5x*((x+1)*(3x-2)))+(=0

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