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2/(x+10)=2x-4
We move all terms to the left:
2/(x+10)-(2x-4)=0
Domain of the equation: (x+10)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
x!=-10
x∈R
2/(x+10)-2x+4=0
We multiply all the terms by the denominator
-2x*(x+10)+4*(x+10)+2=0
We multiply parentheses
-2x^2-20x+4x+40+2=0
We add all the numbers together, and all the variables
-2x^2-16x+42=0
a = -2; b = -16; c = +42;
Δ = b2-4ac
Δ = -162-4·(-2)·42
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{37}}{2*-2}=\frac{16-4\sqrt{37}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{37}}{2*-2}=\frac{16+4\sqrt{37}}{-4} $
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