2/(x+2)+1/5=6/(x+5)

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Solution for 2/(x+2)+1/5=6/(x+5) equation:


D( x )

x+5 = 0

x+2 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-5) U (-5:-2) U (-2:+oo)

2/(x+2)+1/5 = 6/(x+5) // - 6/(x+5)

2/(x+2)-(6/(x+5))+1/5 = 0

2/(x+2)-6*(x+5)^-1+1/5 = 0

2/(x+2)-6/(x+5)+1/5 = 0

(2*5*(x+5))/(5*(x+2)*(x+5))+(-6*5*(x+2))/(5*(x+2)*(x+5))+(1*(x+2)*(x+5))/(5*(x+2)*(x+5)) = 0

2*5*(x+5)-6*5*(x+2)+1*(x+2)*(x+5) = 0

x^2-20*x+7*x-10+10 = 0

x^2-13*x = 0

x^2-13*x = 0

x*(x-13) = 0

x-13 = 0 // + 13

x = 13

x*(x-13) = 0

(x*(x-13))/(5*(x+2)*(x+5)) = 0

(x*(x-13))/(5*(x+2)*(x+5)) = 0 // * 5*(x+2)*(x+5)

x*(x-13) = 0

( x-13 )

x-13 = 0 // + 13

x = 13

( x )

x = 0

x in { 13, 0 }

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