2/(x+3)+1/x=0

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Solution for 2/(x+3)+1/x=0 equation: 



2/(x+3)+1/x=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: x!=0

x∈R



We calculate fractions


2x/(x^2+3x)+(1*(x+3))/(x^2+3x)=0



We calculate terms in parentheses: +(1*(x+3))/(x^2+3x), so:

1*(x+3))/(x^2+3x

We add all the numbers together, and all the variables

3x+1*(x+3))/(x^2

We multiply all the terms by the denominator


3x*(x^2+1*(x+3))

Back to the equation:

+(3x*(x^2+1*(x+3)))



We multiply all the terms by the denominator


2x+((3x*(x^2+1*(x+3))))*(x^2+3x)=0



We calculate terms in parentheses: +((3x*(x^2+1*(x+3))))*(x^2+3x), so:

(3x*(x^2+1*(x+3))))*(x^2+3x

We add all the numbers together, and all the variables

3x+(3x*(x^2+1*(x+3))))*(x^2

Back to the equation:

+(3x+(3x*(x^2+1*(x+3))))*(x^2)

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