2/(x+3)+3/(x-3)=18/(x+3*x-3)

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Solution for 2/(x+3)+3/(x-3)=18/(x+3*x-3) equation: 


D( x )

x+3*x-3 = 0

x-3 = 0

x+3 = 0

x+3*x-3 = 0

x+3*x-3 = 0

4*x-3 = 0 // + 3

4*x = 3 // : 4

x = 3/4

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3/4) U (3/4:3) U (3:+oo)

2/(x+3)+3/(x-3) = 18/(x+3*x-3) // - 18/(x+3*x-3)

2/(x+3)+3/(x-3)-(18/(x+3*x-3)) = 0

2/(x+3)+3/(x-3)-18*(x+3*x-3)^-1 = 0

2/(x+3)+3/(x-3)-18/(4*x-3) = 0

(2*(x-3)*(4*x-3))/((x+3)*(x-3)*(4*x-3))+(3*(x+3)*(4*x-3))/((x+3)*(x-3)*(4*x-3))+(-18*(x+3)*(x-3))/((x+3)*(x-3)*(4*x-3)) = 0

2*(x-3)*(4*x-3)+3*(x+3)*(4*x-3)-18*(x+3)*(x-3) = 0

20*x^2-18*x^2-3*x-9+162 = 0

2*x^2-3*x+153 = 0

2*x^2-3*x+153 = 0

2*x^2-3*x+153 = 0

DELTA = (-3)^2-(2*4*153)

DELTA = -1215

DELTA < 0

1 = 0

1/((x+3)*(x-3)*(4*x-3)) = 0

1/((x+3)*(x-3)*(4*x-3)) = 0 // * (x+3)*(x-3)*(4*x-3)

1 = 0

x belongs to the empty set

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