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2/(x+3)=3/(5-x)
We move all terms to the left:
2/(x+3)-(3/(5-x))=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: (5-x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-5
x!=-5/1
x!=-5
x∈R
2/(x+3)-(3/(-1x+5))=0
We calculate fractions
(-2x)/((x+3)*(-1x+5)))+(-(3*(x+3))/((x+3)*(-1x+5)))=0
We calculate terms in parentheses: -(3*(x+3))/((x+3)*(-1x+5))), so:We add all the numbers together, and all the variables
3*(x+3))/((x+3)*(-1x+5))
We multiply all the terms by the denominator
3*(x+3))
We multiply parentheses
3x+
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
-3x+(-2x)/((x+3)*(-1x+5)))+(=0
We multiply all the terms by the denominator
-3x*((x+3)*(-1x+5)))+(+(-2x)=0
We get rid of parentheses
-3x*((x+3)*(-1x+5)))+(-2x=0
We add all the numbers together, and all the variables
-2x-3x*((x+3)*(-1x+5)))+(=0
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