2/(x+4)=5/(3x+5)

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Solution for 2/(x+4)=5/(3x+5) equation: 



2/(x+4)=5/(3x+5)

We move all terms to the left:

2/(x+4)-(5/(3x+5))=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: (3x+5))!=0

x∈R



We calculate fractions


6x/((x+4)*(3x+5)))+(-(5*(x+4))/((x+4)*(3x+5)))=0



We calculate terms in parentheses: -(5*(x+4))/((x+4)*(3x+5))), so:

5*(x+4))/((x+4)*(3x+5))

We multiply all the terms by the denominator


5*(x+4))

We multiply parentheses

5x+

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We add all the numbers together, and all the variables

-5x+6x/((x+4)*(3x+5)))+(=0

We multiply all the terms by the denominator


-5x*((x+4)*(3x+5)))+(+6x=0

We add all the numbers together, and all the variables

6x-5x*((x+4)*(3x+5)))+(=0

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