2/(x+8)=15/(3-2x)

Solution for 2/(x+8)=15/(3-2x) equation:

2/(x+8)=15/(3-2x)

We move all terms to the left:

2/(x+8)-(15/(3-2x))=0


Domain of the equation: (x+8)!=0

We move all terms containing x to the left, all other terms to the right

x!=-8

x∈R



Domain of the equation: (3-2x))!=0

We move all terms containing x to the left, all other terms to the right

-2x)!=-3

x!=-3/1

x!=-3

x∈R


We add all the numbers together, and all the variables

2/(x+8)-(15/(-2x+3))=0

We calculate fractions


(-4x)/((x+8)*(-2x+3)))+(-(15*(x+8))/((x+8)*(-2x+3)))=0


We calculate terms in parentheses: -(15*(x+8))/((x+8)*(-2x+3))), so:

15*(x+8))/((x+8)*(-2x+3))

We multiply all the terms by the denominator


15*(x+8))

We multiply parentheses

15x+

We add all the numbers together, and all the variables

15x

Back to the equation:

-(15x)


We add all the numbers together, and all the variables

-15x+(-4x)/((x+8)*(-2x+3)))+(=0

We multiply all the terms by the denominator


-15x*((x+8)*(-2x+3)))+(+(-4x)=0

We get rid of parentheses

-15x*((x+8)*(-2x+3)))+(-4x=0

We add all the numbers together, and all the variables

-4x-15x*((x+8)*(-2x+3)))+(=0