2/(x-2)=(4/x-3)-(1/x+1)

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Solution for 2/(x-2)=(4/x-3)-(1/x+1) equation:


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

2/(x-2) = 4/x-(1/x)-3-1 // - 4/x-(1/x)-3-1

2/(x-2)-(4/x)+1/x+1+3 = 0

2/(x-2)-4*x^-1+1/x+1+3 = 0

2/(x-2)-4/x+1/x+1+3 = 0

(2*x)/(x*(x-2))+(-4*(x-2))/(x*(x-2))+(1*(x-2))/(x*(x-2))+(1*x*(x-2))/(x*(x-2))+(3*x*(x-2))/(x*(x-2)) = 0

1*(x-2)-4*(x-2)+1*x*(x-2)+3*x*(x-2)+2*x = 0

x^2+3*x^2-2*x+x-2*x-6*x-2+8 = 0

x^2+3*x^2-x-2*x-6*x+6 = 0

x^2+3*x^2-3*x-6*x+6 = 0

4*x^2-9*x+6 = 0

4*x^2-9*x+6 = 0

4*x^2-9*x+6 = 0

DELTA = (-9)^2-(4*4*6)

DELTA = -15

DELTA < 0

1 = 0

1/(x*(x-2)) = 0

1/(x*(x-2)) = 0 // * x*(x-2)

1 = 0

x belongs to the empty set

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