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2/(x-5)=3/(2x-3)
We move all terms to the left:
2/(x-5)-(3/(2x-3))=0
Domain of the equation: (x-5)!=0
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
Domain of the equation: (2x-3))!=0We calculate fractions
x∈R
4x/((x-5)*(2x-3)))+(-(3*(x-5))/((x-5)*(2x-3)))=0
We calculate terms in parentheses: -(3*(x-5))/((x-5)*(2x-3))), so:We add all the numbers together, and all the variables
3*(x-5))/((x-5)*(2x-3))
We multiply all the terms by the denominator
3*(x-5))
We multiply parentheses
3x+
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
-3x+4x/((x-5)*(2x-3)))+(=0
We multiply all the terms by the denominator
-3x*((x-5)*(2x-3)))+(+4x=0
We add all the numbers together, and all the variables
4x-3x*((x-5)*(2x-3)))+(=0
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