2/(y+2)+(3/y)=(-y)/(y+2)

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Solution for 2/(y+2)+(3/y)=(-y)/(y+2) equation:


D( y )

y = 0

y+2 = 0

y = 0

y = 0

y+2 = 0

y+2 = 0

y+2 = 0 // - 2

y = -2

y in (-oo:-2) U (-2:0) U (0:+oo)

2/(y+2)+3/y = -y/(y+2) // + -y/(y+2)

2/(y+2)-(-y/(y+2))+3/y = 0

2/(y+2)+y*(y+2)^-1+3/y = 0

2/(y+2)+y/(y+2)+3/y = 0

(2*y)/(y*(y+2))+(y^2)/(y*(y+2))+(3*(y+2))/(y*(y+2)) = 0

3*(y+2)+y^2+2*y = 0

y^2+2*y+3*y+6 = 0

y^2+5*y+6 = 0

y^2+5*y+6 = 0

y^2+5*y+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

y = (1^(1/2)-5)/(1*2) or y = (-1^(1/2)-5)/(1*2)

y = -2 or y = -3

(y+3)*(y+2) = 0

((y+3)*(y+2))/(y*(y+2)) = 0

((y+3)*(y+2))/(y*(y+2)) = 0 // * y*(y+2)

(y+3)*(y+2) = 0

( y+2 )

y+2 = 0 // - 2

y = -2

( y+3 )

y+3 = 0 // - 3

y = -3

y in { -2}

y = -3

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