2/(y-1)=2/y-1

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Solution for 2/(y-1)=2/y-1 equation: 


D( y )

y-1 = 0

y = 0

y-1 = 0

y-1 = 0

y-1 = 0 // + 1

y = 1

y = 0

y = 0

y in (-oo:0) U (0:1) U (1:+oo)

2/(y-1) = 2/y-1 // - 2/y-1

2/(y-1)-(2/y)+1 = 0

2/(y-1)-2*y^-1+1 = 0

2/(y-1)-2/y+1 = 0

(2*y)/(y*(y-1))+(-2*(y-1))/(y*(y-1))+(1*y*(y-1))/(y*(y-1)) = 0

1*y*(y-1)-2*(y-1)+2*y = 0

y^2-y+2 = 0

y^2-y+2 = 0

y^2-y+2 = 0

DELTA = (-1)^2-(1*2*4)

DELTA = -7

DELTA < 0

1 = 0

1/(y*(y-1)) = 0

1/(y*(y-1)) = 0 // * y*(y-1)

1 = 0

y belongs to the empty set

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