2/(z+5)=12

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Solution for 2/(z+5)=12 equation: 



2/(z+5)=12

We move all terms to the left:

2/(z+5)-(12)=0



Domain of the equation: (z+5)!=0

We move all terms containing z to the left, all other terms to the right

z!=-5

z∈R



We multiply all the terms by the denominator


-12*(z+5)+2=0

We multiply parentheses

-12z-60+2=0

We add all the numbers together, and all the variables

-12z-58=0

We move all terms containing z to the left, all other terms to the right

-12z=58

z=58/-12

z=-4+5/6

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