2/1(3y+2)-8/5=4/3y

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Solution for 2/1(3y+2)-8/5=4/3y equation: 



2/1(3y+2)-8/5=4/3y

We move all terms to the left:

2/1(3y+2)-8/5-(4/3y)=0



Domain of the equation: 1(3y+2)!=0

y∈R





Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

2/1(3y+2)-(+4/3y)-8/5=0

We get rid of parentheses

2/1(3y+2)-4/3y-8/5=0

We calculate fractions


(-20y3/(1(3y+2)*3y*5)+(-24y^23/(1(3y+2)*3y*5)+150y/(1(3y+2)*3y*5)=0



We calculate terms in parentheses: +(-20y3/(1(3y+2)*3y*5)+(-24y^23/(1(3y+2)*3y*5)+150y/(1(3y+2)*3y*5), so:

-20y3/(1(3y+2)*3y*5)+(-24y^23/(1(3y+2)*3y*5)+150y/(1(3y+2)*3y*5

We do not support eypression: y^23

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