2/10+3(2x+2)=1+40x

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Solution for 2/10+3(2x+2)=1+40x equation: 


x in (-oo:+oo)

3*(2*x+2)+2/10 = 40*x+1 // - 40*x+1

3*(2*x+2)-(40*x)+2/10-1 = 0

3*(2*x+2)-40*x+2/10-1 = 0

3*(2*x+2)-40*x+1/5-1 = 0

(3*5*(2*x+2))/5+(-40*5*x)/5+1/5+(-1*5)/5 = 0

3*5*(2*x+2)-40*5*x-1*5+1 = 0

1-170*x-5+30 = 0

31-170*x-5 = 0

26-170*x = 0

(26-170*x)/5 = 0

(26-170*x)/5 = 0 // * 5

26-170*x = 0

26-170*x = 0 // - 26

-170*x = -26 // : -170

x = -26/(-170)

x = 13/85

x = 13/85

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