2/18+1/6a=1/3a

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Solution for 2/18+1/6a=1/3a equation:



2/18+1/6a=1/3a
We move all terms to the left:
2/18+1/6a-(1/3a)=0
Domain of the equation: 6a!=0
a!=0/6
a!=0
a∈R
Domain of the equation: 3a)!=0
a!=0/1
a!=0
a∈R
We add all the numbers together, and all the variables
1/6a-(+1/3a)+2/18=0
We get rid of parentheses
1/6a-1/3a+2/18=0
We calculate fractions
108a^2/324a^2+54a/324a^2+(-108a)/324a^2=0
We multiply all the terms by the denominator
108a^2+54a+(-108a)=0
We get rid of parentheses
108a^2+54a-108a=0
We add all the numbers together, and all the variables
108a^2-54a=0
a = 108; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·108·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*108}=\frac{0}{216} =0 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*108}=\frac{108}{216} =1/2 $

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