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2/1m+16=4+6/11m
We move all terms to the left:
2/1m+16-(4+6/11m)=0
Domain of the equation: 1m!=0
m∈R
Domain of the equation: 11m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
2/1m-(6/11m+4)+16=0
We get rid of parentheses
2/1m-6/11m-4+16=0
We calculate fractions
22m/11m^2+(-6m)/11m^2-4+16=0
We add all the numbers together, and all the variables
22m/11m^2+(-6m)/11m^2+12=0
We multiply all the terms by the denominator
22m+(-6m)+12*11m^2=0
Wy multiply elements
132m^2+22m+(-6m)=0
We get rid of parentheses
132m^2+22m-6m=0
We add all the numbers together, and all the variables
132m^2+16m=0
a = 132; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·132·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*132}=\frac{-32}{264} =-4/33 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*132}=\frac{0}{264} =0 $
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