2/2(y+9)-2=1/2(y+9)

Solution for 2/2(y+9)-2=1/2(y+9) equation:

2/2(y+9)-2=1/2(y+9)

We move all terms to the left:

2/2(y+9)-2-(1/2(y+9))=0


Domain of the equation: 2(y+9)!=0

y∈R



Domain of the equation: 2(y+9))!=0

y∈R


We calculate fractions


(4yy/(2(y+9)*2(y+9)))+(-2yy/(2(y+9)*2(y+9)))-2=0


We calculate terms in parentheses: +(4yy/(2(y+9)*2(y+9))), so:

4yy/(2(y+9)*2(y+9))

We multiply all the terms by the denominator


4yy

Back to the equation:

+(4yy)



We calculate terms in parentheses: +(-2yy/(2(y+9)*2(y+9))), so:

-2yy/(2(y+9)*2(y+9))

We multiply all the terms by the denominator


-2yy

Back to the equation:

+(-2yy)


We get rid of parentheses

4yy-2yy-2=0

We move all terms containing y to the left, all other terms to the right

4yy-2yy=2