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2/2x+2x+4=-4
We move all terms to the left:
2/2x+2x+4-(-4)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+2/2x+8=0
We multiply all the terms by the denominator
2x*2x+8*2x+2=0
Wy multiply elements
4x^2+16x+2=0
a = 4; b = 16; c = +2;
Δ = b2-4ac
Δ = 162-4·4·2
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{14}}{2*4}=\frac{-16-4\sqrt{14}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{14}}{2*4}=\frac{-16+4\sqrt{14}}{8} $
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