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2/2x=3/x+6
We move all terms to the left:
2/2x-(3/x+6)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+6)!=0We get rid of parentheses
x∈R
2/2x-3/x-6=0
We calculate fractions
2x/2x^2+(-6x)/2x^2-6=0
We multiply all the terms by the denominator
2x+(-6x)-6*2x^2=0
Wy multiply elements
-12x^2+2x+(-6x)=0
We get rid of parentheses
-12x^2+2x-6x=0
We add all the numbers together, and all the variables
-12x^2-4x=0
a = -12; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-12)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-12}=\frac{0}{-24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-12}=\frac{8}{-24} =-1/3 $
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