2/2y=2/2(y-2)

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Solution for 2/2y=2/2(y-2) equation: 


y in (-oo:+oo)

(2/2)*y = (2/2)*(y-2) // - (2/2)*(y-2)

(2/2)*y-((2/2)*(y-2)) = 0

(2/2)*y-y+2 = 0

2 = 0

y belongs to the empty set

y belongs to the empty set

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