2/3(-6+6x)=2/3(x+9)

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Solution for 2/3(-6+6x)=2/3(x+9) equation:



2/3(-6+6x)=2/3(x+9)
We move all terms to the left:
2/3(-6+6x)-(2/3(x+9))=0
Domain of the equation: 3(-6+6x)!=0
x∈R
Domain of the equation: 3(x+9))!=0
x∈R
We add all the numbers together, and all the variables
2/3(6x-6)-(2/3(x+9))=0
We calculate fractions
(6xx/(3(6x-6)*3(x+9)))+(-6x6/(3(6x-6)*3(x+9)))=0
We calculate terms in parentheses: +(6xx/(3(6x-6)*3(x+9))), so:
6xx/(3(6x-6)*3(x+9))
We multiply all the terms by the denominator
6xx
Back to the equation:
+(6xx)
We calculate terms in parentheses: +(-6x6/(3(6x-6)*3(x+9))), so:
-6x6/(3(6x-6)*3(x+9))
We multiply all the terms by the denominator
-6x6
We add all the numbers together, and all the variables
-6x^6
We do not support expression: x^6

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