2/3(-6x+3)=-3(8x-4)

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Solution for 2/3(-6x+3)=-3(8x-4) equation:



2/3(-6x+3)=-3(8x-4)
We move all terms to the left:
2/3(-6x+3)-(-3(8x-4))=0
Domain of the equation: 3(-6x+3)!=0
x∈R
We multiply all the terms by the denominator
-((-3(8x-4)))*3(-6x+3)+2=0
We calculate terms in parentheses: -((-3(8x-4)))*3(-6x+3), so:
(-3(8x-4)))*3(-6x+3
We add all the numbers together, and all the variables
-6x+(-3(8x-4)))*3(+3
Back to the equation:
-(-6x+(-3(8x-4)))*3(+3)
We add all the numbers together, and all the variables
-(-6x+(-3(8x-4)))*33+2=0
We move all terms containing x to the left, all other terms to the right
-(-6x+(-3(8x-4)))*33=-2

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