2/3(-6x+3)=-3(8x-4)

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Solution for 2/3(-6x+3)=-3(8x-4) equation: 



2/3(-6x+3)=-3(8x-4)

We move all terms to the left:

2/3(-6x+3)-(-3(8x-4))=0



Domain of the equation: 3(-6x+3)!=0

x∈R



We multiply all the terms by the denominator


-((-3(8x-4)))*3(-6x+3)+2=0



We calculate terms in parentheses: -((-3(8x-4)))*3(-6x+3), so:

(-3(8x-4)))*3(-6x+3

We add all the numbers together, and all the variables

-6x+(-3(8x-4)))*3(+3

Back to the equation:

-(-6x+(-3(8x-4)))*3(+3)



We add all the numbers together, and all the variables

-(-6x+(-3(8x-4)))*33+2=0

We move all terms containing x to the left, all other terms to the right

-(-6x+(-3(8x-4)))*33=-2

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