2/3(1+n)=-1/2(n)

Solution for 2/3(1+n)=-1/2(n) equation:

2/3(1+n)=-1/2(n)

We move all terms to the left:

2/3(1+n)-(-1/2(n))=0


Domain of the equation: 3(1+n)!=0

n∈R



Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

2/3(n+1)-(-1/2n)=0

We get rid of parentheses

2/3(n+1)+1/2n=0

We calculate fractions


4n/(6n^2+6n)+(3nn/(6n^2+6n)=0


We calculate terms in parentheses: +(3nn/(6n^2+6n), so:

3nn/(6n^2+6n

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)


We multiply all the terms by the denominator


4n+3nn*(6n^2+6n)=0

We multiply parentheses

18n^3+18n^2+4n=0

We do not support enpression: n^3