2/3(1+n)=-1/2n.

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Solution for 2/3(1+n)=-1/2n. equation: 



2/3(1+n)=-1/2n.

We move all terms to the left:

2/3(1+n)-(-1/2n.)=0



Domain of the equation: 3(1+n)!=0

n∈R





Domain of the equation: 2n.)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

2/3(n+1)-(-1/2n.)=0

We get rid of parentheses

2/3(n+1)+1/2n.=0

We calculate fractions


4n/(6n^2+6n)+(3nn/(6n^2+6n)=0



We calculate terms in parentheses: +(3nn/(6n^2+6n), so:

3nn/(6n^2+6n

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)



We multiply all the terms by the denominator


4n+3nn*(6n^2+6n)=0

We multiply parentheses

18n^3+18n^2+4n=0

We do not support enpression: n^3

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