2/3(1+n)=-1/n

Solution for 2/3(1+n)=-1/n equation:

2/3(1+n)=-1/n

We move all terms to the left:

2/3(1+n)-(-1/n)=0


Domain of the equation: 3(1+n)!=0

n∈R



Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

2/3(n+1)-(-1/n)=0

We get rid of parentheses

2/3(n+1)+1/n=0

We calculate fractions


2n/(3n^2+3n)+(3nn/(3n^2+3n)=0


We calculate terms in parentheses: +(3nn/(3n^2+3n), so:

3nn/(3n^2+3n

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)


We multiply all the terms by the denominator


2n+3nn*(3n^2+3n)=0

We multiply parentheses

9n^3+9n^2+2n=0

We do not support enpression: n^3