2/3(1+n)=1/2n

Solution for 2/3(1+n)=1/2n equation:

2/3(1+n)=1/2n

We move all terms to the left:

2/3(1+n)-(1/2n)=0


Domain of the equation: 3(1+n)!=0

n∈R



Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

2/3(n+1)-(+1/2n)=0

We get rid of parentheses

2/3(n+1)-1/2n=0

We calculate fractions


4n/(6n^2+6n)+(-3nn/(6n^2+6n)=0


We calculate terms in parentheses: +(-3nn/(6n^2+6n), so:

-3nn/(6n^2+6n

We multiply all the terms by the denominator


-3nn

Back to the equation:

+(-3nn)


We get rid of parentheses

4n/(6n^2+6n)-3nn=0

We multiply all the terms by the denominator


4n-3nn*(6n^2+6n)=0

We multiply parentheses

-18n^3-18n^2+4n=0

We do not support enpression: n^3