2/3(1/8+8x)-1/8=7/8

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Solution for 2/3(1/8+8x)-1/8=7/8 equation: 


x in (-oo:+oo)

(2/3)*(8*x+1/8)-(1/8) = 7/8 // - 7/8

(2/3)*(8*x+1/8)-(1/8)-(7/8) = 0

(2/3)*(8*x+1/8)-1/8-7/8 = 0

2/3*(8*x+1/8)-1/8-7/8 = 0

(2/3*8*(8*x+1/8))/8-1/8-7/8 = 0

2/3*8*(8*x+1/8)-7-1 = 0

128/3*x-7-1/3 = 0

128/3*x-22/3 = 0

(128/3*x-22/3)/8 = 0

(128/3*x-22/3)/8 = 0 // * 8

128/3*x-22/3 = 0

128/3*x-22/3 = 0 // + 22/3

128/3*x = 22/3 // : 128/3

x = 22/3/128/3

x = 11/64

x = 11/64

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