2/3(12+60x)+5=1/2(26+10x)

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Solution for 2/3(12+60x)+5=1/2(26+10x) equation: 



2/3(12+60x)+5=1/2(26+10x)

We move all terms to the left:

2/3(12+60x)+5-(1/2(26+10x))=0



Domain of the equation: 3(12+60x)!=0

x∈R





Domain of the equation: 2(26+10x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(60x+12)-(1/2(10x+26))+5=0

We calculate fractions


(4x1/(3(60x+12)*2(10x+26)))+(-3x6/(3(60x+12)*2(10x+26)))+5=0



We calculate terms in parentheses: +(4x1/(3(60x+12)*2(10x+26))), so:

4x1/(3(60x+12)*2(10x+26))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-3x6/(3(60x+12)*2(10x+26))), so:

-3x6/(3(60x+12)*2(10x+26))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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