2/3(12-3a)=4(a+8)

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Solution for 2/3(12-3a)=4(a+8) equation: 



2/3(12-3a)=4(a+8)

We move all terms to the left:

2/3(12-3a)-(4(a+8))=0



Domain of the equation: 3(12-3a)!=0

a∈R



We add all the numbers together, and all the variables

2/3(-3a+12)-(4(a+8))=0

We multiply all the terms by the denominator


-((4(a+8)))*3(-3a+12)+2=0



We calculate terms in parentheses: -((4(a+8)))*3(-3a+12), so:

(4(a+8)))*3(-3a+12

We add all the numbers together, and all the variables

-3a+(4(a+8)))*3(+12

Back to the equation:

-(-3a+(4(a+8)))*3(+12)



We add all the numbers together, and all the variables

-(-3a+(4(a+8)))*312+2=0

We move all terms containing a to the left, all other terms to the right

-(-3a+(4(a+8)))*312=-2

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