2/3(12-5d)

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Solution for 2/3(12-5d) equation: 


d in (-oo:+oo)

(2/3)*(12-(5*d)) = 0

(2/3)*(12-5*d) = 0

2/3*(12-5*d) = 0

( 12-5*d )

12-5*d = 0 // - 12

-5*d = -12 // : -5

d = -12/(-5)

d = 12/5

( 2/3 )

2/3 = 0

d belongs to the empty set

d = 12/5

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