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2/3(12-9y)=2y-8
We move all terms to the left:
2/3(12-9y)-(2y-8)=0
Domain of the equation: 3(12-9y)!=0We add all the numbers together, and all the variables
y∈R
2/3(-9y+12)-(2y-8)=0
We get rid of parentheses
2/3(-9y+12)-2y+8=0
We multiply all the terms by the denominator
-2y*3(-9y+12)+8*3(-9y+12)+2=0
Wy multiply elements
-6y^2(-+24y(-+2=0
We use the square of the difference formula
-6y^2(-24y(-2=0
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