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2/3(12x+2)=5+1/3(9x+4)
We move all terms to the left:
2/3(12x+2)-(5+1/3(9x+4))=0
Domain of the equation: 3(12x+2)!=0
x∈R
Domain of the equation: 3(9x+4))!=0We calculate fractions
x∈R
(6x9/(3(12x+2)*3(9x+4)))+(-3x1/(3(12x+2)*3(9x+4)))=0
We calculate terms in parentheses: +(6x9/(3(12x+2)*3(9x+4))), so:
6x9/(3(12x+2)*3(9x+4))
We multiply all the terms by the denominator
6x9
We add all the numbers together, and all the variables
6x^9
We do not support expression: x^9
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